Post by Charles BrennerPost by Bruce EvansPost by Dave FlowerPost by Charles BrennerPost by Dave FlowerThis hand is a variation on the hand that appeared in last
Saturday's (London) Times.
Post by Charles BrennerPost by Dave FlowerIgnoring the excellent contract of 7S, South plays in 6H on a trump
Q J x x x
J
K Q x
10 9 x x
A K
A K Q 10 9 8
A
A Q x x
Against one particular lie of the E/W cards, there is a chance for a
brilliancy; can you spot it ?
Post by Charles BrennerIf declarer strips trumps & the top spades & diamond then exits a LOW
club (thinking it is just as good exiting Q -- but not quite as we'll
see), RHO stands a chance to beat you by brilliantly winning with the
King. You might think that the fine LHO player with Jx(x) realized that
putting up the J was suicide and therefore ducked to RHO's Kx(x) -- in
which case you'd need to play high on the second round of clubs.
Post by Charles BrennerAlternatively, if you say that even when RHO wins the club K you'd
play RHO for KJxx and finesse on the way back, then it's LHO's duck from
Jx(x) that is a brilliancy.
I missed this in a previous analysis. Also, I misanalyzed KJxx(x)
with West in the Q lead case. West ducks, but now South simply plays
low to endplay him. All KJxx(x) layouts can be handled.
To give fair credit to Lorne, that was no doubt his point.
Post by Bruce EvansThis gives 10 losing cases for low and 6 losing cases for the Q.
10? I see at most 9, and realistically more like 6.
Yes, the 10th losing case was forgetting that East is endplayed if
he wins the singleton J.
Post by Charles BrennerUnless you credit RHO with winning K from KJxx when declarer exits low,
low and Q are equally effective.
I did credit RHO with that after you pointed it out. If he thinks about
it, then this play is not much harder than not going up with Jx or Kx as
LHO.
Post by Charles BrennerEvery winning case for one of them
corresponds to a winning case for the other by exchanging K for J. There
are 6 losing cases for both against pedestrian defenders. Against a
brilliant RHO there are still not 10 losing cases for low, only 9.
The 6 simpler losing cases for low are Kx and Kxx with LHO, while the
6 losing cases for the Q are Jx and Jxx with LHO. I think it is easier
to play low with the K than with the J, so I now think low is better
unless RHO will find the brilliancy.
Er, I have miscounted again. RHO can find the brilliancy with both
KJx or KJxx. If I don't play for the falsecard then this gives 12
losing cases, not 9. And if I do play for the falsecard and always
finesse on return of a low club by RHO, then the extra 6 losing cases
are exchanged with ones where LHO has Jx or Jxx.
The 12 losing cases can be reduced a bit by looking at the spots.
LHO with xx and RHO with KJxx must choose the spot very carefully
to avoid exposing any falsecard. Similary for the 3-2 breaks.
But it is a waste of time to worry about this before knowing the
trump break and the discards.
Post by Charles BrennerPost by Bruce EvansPost by Dave FlowerAh, perhaps I didn't take parse David's wording precisely enough -- the
above answers the question "*With* one particular like of the EW cards
..." rather than *Against*.
Assuming the brilliancy should be by declarer, I'm trying to imagine
what happens when a 6-0 trump break means pulling trumps squeezes the
dummy.
Now I see "one" possibilty. Dummy is squeezed down to T9x of clubs even
if trumps are 5-1. Now KJxx(x) with West cannot be handled by the Q lead.
West ducks and then pins dummy's T9 with the KJ. West's spots are actually
equivalent to the 87.
One could assume, but really I think we should have been told more of the club spots.
I just assumed that they are really x's. They must be 5432 for that.
And then the opponent's spots will be contiguous and it will be easier
for the opponents to falsecard with them.
Post by Charles BrennerPost by Bruce EvansThis gives 10 losing cases for the Q lead again.
Yes, that's good. So if trumps are 5-1 declarer should probably exit low.
Post by Bruce EvansIf trumps are 6-0, then dummy might be squeezed down to the T9 of clubs
and these can be pinned without ducking anything.
That was my point. Since David wrote "one particular lie" he might have
had in mind the situation that RHO discards on the first trump and the
second spade, while LHO shows void in diamonds. Then we know the clubs
are 2=3 -- for whatever good that does.
It is now clear that "one lie" can only be in the club suit since there
are many interesting lies of the club suit combined with others. And "one"
is still actually 2 or 6 depending on whether different spots give
different lies -- KJx and KJxx with RHO.
Bruce